lizhendong
級別: 家園常客
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這個函數原理和調用????C的高手看看!!! static const char sel[] = { 'B','C','D','F','G', 'H','J','K','M','P', 'Q','R','T','V','W', 'X','Y','2','3','4', '6','7','8','9', '\0'}; char *b24e(char *buf, unsigned char *byst, size_t sizeOfBytes) { int i = 0; unsigned char *p = byst; while ((size_t)(i = (p-byst)) < sizeOfBytes) { buf[2*i] = sel[((*p) >> 4)]; buf[(2*i)+1] = sel[23 - ((*p) & 0x0f)]; p++; } buf[(2*i)+1] = '\0'; return buf; } unsigned char *b24d(unsigned char *buf, char *str, size_t countOfChars) { size_t i; char *p = str; char *loc[2]; unsigned char n[2]; if (countOfChars % 2) return NULL; for (i = 0; i < (countOfChars>>1); i++) { loc[0] = strchr( sel, str[2*i] ); loc[1] = strchr( sel, str[ ( 2*i ) + 1 ] ); if (loc[0] == NULL || loc[1] == NULL) return NULL; n[0] = (unsigned char)( loc[0] - sel ); n[1] = 23 - (unsigned char)( loc[1] - sel ); buf = (unsigned char)((n[0] << 4) | n[1]); } return buf; } |
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13821917697
承接電氣自動化項目、電氣接線圖設計、IO點表、電氣元器件選型
級別: 工控俠客
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圖片:
好像就是類似動態密碼的東西,把你輸入的東西,按照這個轉換成一個碼,碼由你最上面定義的那個字符數組組成。 |
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